Let the initial velocity of the object = u Let the object is moving with uniform acceleration, aThe three equations of motion v = u + at ; s = ut + (1/2) at2 and v2 = u2 + 2as can be derived with the help of graphs as described belowAnd this is the first equation of motionThis equation can be rearranged to give: (2) But from the graph BC = BD + DC Therefore, v = BD + DC

Motion along a circular path: Motion of an object along a circular path is called circular motionThus: 9th science Motion PreviousNextChapter list Equation for Velocity Time relation by graphical method First equation of Motion Let an object is moving with uniform accelerationa = BD/t or BD = at (5) (ii) Area of triangle ABD = (1/2) Area of rectangle AEBD = (1/2) AD BD = (1/2) t at (because AD = t and BD = at) = (1/2) at2.Now, Initial velocity of the body, u = OAWe can't find what you were looking for

Suppose the body travels a distance s in time tDerive s = ut + (1/2) at2 by Graphical Method Velocity in the case of circular motionWhatever you were looking for was not found, but maybe try looking again or search using the form below.It is called first equation of motion(1) And, Final velocity of the body, v = BC

It has been derived here by the graphical methodDistance travelled = Area of figure OABC = Area of rectangle OADC + Area of triangle ABD To complete the figure, we draw the perpendicular CB from point C, and draw AD parallel to OCThe time t is represented by OCNow, putting this value of BD in equation (4) we get :

Equation for distance time relation Distance covered by the object in the given time t is given by the area of the trapezium ABDOE Let in the given time, t the distance covered by the moving object = s The area of trapezium, ABDOE = Distance (s) = Area of triangle ABD + Area of ADOE =>s = 1/2 xx AB xx AD + (ODxxOE) =>s = 1/2 xx DC xx AD + (u+t) [Since, AB = DC] =>s=1/2xx at xx t + ut =>s=1/2xxatxxt+ut [∵ DC=at] =>s=1/2at^2+ut =>s=ut+1/2at^2 The above expression gives the distance covered by the object moving with uniform accelerationEquation for Distance Velocity Relation: Third equation of Motion: The distance covered by the object moving with uniform acceleration is given by the area of trapezium ABDO Therefore, Area of trapezium ABDOE =1/2xx(text{sum of parallel sides+distance between parallel sides}) ⇒ Distance (s) =1/2(DO+BE) xx OE =>s= 1/2(u+v) xxt ----(iii) Now from equation (ii) a=(v-u)/t :21Draw another line BA from point B parallel to y-axis which meets at E at y-axisso putting t in place of AD in the above relation, we get: 87c6bb4a5b

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